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1 Select the Elliptical Marquee tool from the toolbox and set the Feather in the Options bar to 2 pixels 2 Use this tool to draw a circular selection first around the red portion of the left eye 3 Hold down the SHIFT key and repeat the process with the right eye until you have the red-eye selected from both eyes 4 Choose Image | Adjustments | Channel Mixer 5 By default, in an RGB image, the Red channel is selected in the Channel Mixer Under Source Channels, set the value for Red back to 0 and increase the value of the other two channels (Green and Blue) to equal 100% I usually set them each to 50%, but you can try other combinations depending on which color to emphasize 6 Click OK to complete the process

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4 B The job will, by default, not be enabled and therefore cannot run A, C, and D A is wrong because the job is not controlled by a window, but by a schedule C is wrong because while the Resource Manager can control job priority, it would not in most circumstances block a job completely D is wrong because while permissions might cause a job to fail, they would not stop it from running 5 A Job priorities are 1 to 5 (highest to lowest) B, C, and D B is wrong because it is the incorrect range C is the choice for window priority, not job priority D is wrong because the Resource Manager controls priorities between classes, not within them 6 A and B Both will provide a half-hour repeat interval C, D, and E C is the syntax for a window s duration, not a repeat interval D and E are syntactically wrong: there is no such specifier as BYMINUTE (though such a specifier might be useful) 7 B With logging set to LOGGING_RUNS, you will get records of each run of each job, including the success or failure A, C, and D A is wrong because LOGGING_RUNS will include the success or failure C and D are wrong because even though logging is set at the class level, it is applied at the job level Note that logging can also be set at the job level 8 A and D Many jobs can be controlled by one schedule, and Scheduler priorities are applied to jobs within classes B, C, E, and F B and C both misunderstand the many-to-one relationships of Scheduler objects E is wrong because consumer groups control priorities between classes, not within them F is wrong because plans are activated by windows, not schedules 9 D The DBA_SCHEDULER_JOBS view externalizes the data dictionary jobs table, with one row per scheduled job A, B, and C A is wrong because DBA_JOBS describes the jobs scheduled through the old DBMS_JOB system B and C refer to views that do not exist 10 E Other things being equal, the window with the longest to run will open (or remain open) A, B, C, and D Only one window can be open at once, and windows can overlap The algorithms that manage overlapping windows are not well documented, but neither C nor D is definitively correct.

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